The geometric sequence aₙ = 3·0.5ⁿ⁻¹ decreases. Find the first index n for which aₙ < 0.2.
Sequences & series worksheet with answers
1.Easy
a₁ = 3r = 0.5ε = 0.2
n =
2.Easy
Find the sum S of the infinite series Σk=0∞ 10·(−1/3)ᵏ.
a = 10r = −1/3k₀ = 0
S =
3.Medium
Apply the ratio test to Σk=1∞ (k!)²·2ᵏ/(2k)!. Find L = lim |ak+1/ak|.
ak = (k!)²·2ᵏ/(2k)!
L =
4.Medium
Exactly one of the four series converges. Click it.
A: Σ (2/3)ᵏB: Σ (1 + 1/k)ᵏC: Σ (7/4)ᵏD: Σ (k + 2)/k²
- 1A: Σ (2/3)ᵏ
- 2B: Σ (1 + 1/k)ᵏ
- 3C: Σ (7/4)ᵏ
- 4D: Σ (k + 2)/k²
5.Hard
f(x) = sin x is approximated at x = 1 by its Maclaurin polynomial of degree n. With the Lagrange bound M·|x|ⁿ⁺¹/(n + 1)! and M = 1, find the smallest degree n that guarantees an error below 1 × 10⁻⁶.
f(x) = sin xx = 1M = 1ε = 1 × 10⁻⁶
n =
6.Hard
Recognise the series and find its sum: S = Σk=1∞ k·0.2ᵏ.
ak = k·0.2ᵏ
S =
Answer key
- 1. n = 5
- 2. S = 7.5
- 3. L = 0.5
- 4. A: Σ (2/3)ᵏ
- 5. n = 9
- 6. S = 0.3125
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