The geometric sequence aₙ = 20·0.9ⁿ⁻¹ decreases. Find the first index n for which aₙ < 0.05.
Sequences & series worksheet with answers
1.Easy
a₁ = 20r = 0.9ε = 0.05
n =
2.Easy
Find the sum S of the infinite series Σk=1∞ 6·(1/3)ᵏ.
a = 6r = 1/3k₀ = 1
S =
3.Medium
Apply the ratio test to Σk=1∞ k!/kᵏ. Find L = lim |ak+1/ak|.
ak = k!/kᵏ
L =
4.Medium
Find the sum S = Σk=1∞ 5/(k(k + 4)).
ak = 5/(k(k + 4))
S =
5.Hard
Recognise the series and find its sum: S = Σk=1∞ k·(−0.5)ᵏ.
ak = k·(−0.5)ᵏ
S =
6.Hard
f(x) = eˣ is approximated at x = 0.5 by its Maclaurin polynomial of degree n. With the Lagrange bound M·|x|ⁿ⁺¹/(n + 1)! and M = 2, find the smallest degree n that guarantees an error below 0.0005.
f(x) = eˣx = 0.5M = 2ε = 0.0005
n =
Answer key
- 1. n = 58
- 2. S = 3
- 3. L = 0.3679
- 4. S = 2.604
- 5. S = −0.2222
- 6. n = 5
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