The geometric sequence aₙ = 20·0.85ⁿ⁻¹ decreases. Find the first index n for which aₙ < 0.5.
Sequences & series worksheet with answers
1.Easy
a₁ = 20r = 0.85ε = 0.5
n =
2.Easy
The arithmetic sequence 7, 5, 3, 1, … ends with the term −17. How many terms n does it have?
a₁ = 7d = −2aₙ = −17
n =
3.Medium
Exactly one of the four series diverges. Click it.
A: Σ 1/(2ᵏ + k)B: Σ 2/kC: Σ 1/k⁴D: Σ (2/5)ᵏ
- 1A: Σ 1/(2ᵏ + k)
- 2B: Σ 2/k
- 3C: Σ 1/k⁴
- 4D: Σ (2/5)ᵏ
4.Medium
Exactly one of the four series converges. Click it.
A: Σ (5/4)ᵏB: Σ 1/kC: Σ (3/5)ᵏD: Σ 2ᵏ/k³
- 1A: Σ (5/4)ᵏ
- 2B: Σ 1/k
- 3C: Σ (3/5)ᵏ
- 4D: Σ 2ᵏ/k³
5.Hard
f(x) = sin x is approximated at x = 2 by its Maclaurin polynomial of degree n. With the Lagrange bound M·|x|ⁿ⁺¹/(n + 1)! and M = 1, find the smallest degree n that guarantees an error below 1 × 10⁻⁵.
f(x) = sin xx = 2M = 1ε = 1 × 10⁻⁵
n =
6.Hard
Use the Maclaurin polynomial of degree 3 of f(x) = ln(1 − x) to approximate f(0.5). Give P₃(0.5).
f(x) = ln(1 − x)n = 3x = 0.5
P₃(0.5) =
Answer key
- 1. n = 24
- 2. n = 13
- 3. B: Σ 2/k
- 4. C: Σ (3/5)ᵏ
- 5. n = 11
- 6. P₃(0.5) = −0.6667
Full step-by-step solutions: practise this topic on examproblems.com.