The geometric sequence aₙ = 2·0.8ⁿ⁻¹ decreases. Find the first index n for which aₙ < 0.5.
Sequences & series worksheet with answers
1.Easy
a₁ = 2r = 0.8ε = 0.5
n =
2.Easy
Find the sum S28 of the first 28 terms of the arithmetic sequence 14, 16, 18, 20, …
a₁ = 14d = 2n = 28
S28 =
3.Medium
Apply the ratio test to Σk=1∞ k!/kᵏ. Find L = lim |ak+1/ak|.
ak = k!/kᵏ
L =
4.Medium
Apply the ratio test to Σk=1∞ kᵏ/(3ᵏ·k!). Find L = lim |ak+1/ak|.
ak = kᵏ/(3ᵏ·k!)
L =
5.Hard
f(x) = eˣ is approximated at x = 1 by its Maclaurin polynomial of degree n. With the Lagrange bound M·|x|ⁿ⁺¹/(n + 1)! and M = 3, find the smallest degree n that guarantees an error below 0.0001.
f(x) = eˣx = 1M = 3ε = 0.0001
n =
6.Hard
f(x) = cos x is approximated by its Maclaurin polynomial of degree 5 at x = 0.5. Use the Lagrange error bound M·|x|ⁿ⁺¹/(n + 1)! with M = 1 to find the largest possible error |R₅|.
f(x) = cos xn = 5x = 0.5M = 1
|R₅| =
Answer key
- 1. n = 8
- 2. S28 = 1148
- 3. L = 0.3679
- 4. L = 0.9061
- 5. n = 7
- 6. |R₅| = 2.17 × 10⁻⁵
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