Find the term a21 of the arithmetic sequence 18, 24, 30, 36, …
Sequences & series worksheet with answers
1.Easy
a₁ = 18d = 6n = 21
a21 =
2.Easy
Find the sum S8 of the first 8 terms of the geometric sequence 4, −8, 16, …
a₁ = 4r = −2n = 8
S8 =
3.Medium
Apply the ratio test to Σk=1∞ (k!)²·3ᵏ/(2k)!. Find L = lim |ak+1/ak|.
ak = (k!)²·3ᵏ/(2k)!
L =
4.Medium
Exactly one of the four series converges. Click it.
A: Σ (k + 3)/k²B: Σ (5/3)ᵏC: Σ 1/(k(k + 3))D: Σ 2ᵏ/k²
- 1A: Σ (k + 3)/k²
- 2B: Σ (5/3)ᵏ
- 3C: Σ 1/(k(k + 3))
- 4D: Σ 2ᵏ/k²
5.Hard
Recognise the series and find its sum: S = Σk=0∞ 0.5ᵏ/k!.
ak = 0.5ᵏ/k!
S =
6.Hard
f(x) = cos x is approximated at x = 1.5 by its Maclaurin polynomial of degree n. With the Lagrange bound M·|x|ⁿ⁺¹/(n + 1)! and M = 1, find the smallest degree n that guarantees an error below 0.001.
f(x) = cos xx = 1.5M = 1ε = 0.001
n =
Answer key
- 1. a21 = 138
- 2. S8 = −340
- 3. L = 0.75
- 4. C: Σ 1/(k(k + 3))
- 5. S = 1.649
- 6. n = 7
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