Shear force & bending moment worksheet with answers

Free printable Shear force & bending moment worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
20 kNABCDEFG1 m1 m1 m1 m1 m1 m

The marks A to G split the beam into six equal parts. At which mark is the bending moment largest in size, sagging or hogging? Click it in the diagram.

20 kN @ 4 m
  1. 1A (x = 0 m)
  2. 2B (x = 1 m)
  3. 3C (x = 2 m)
  4. 4D (x = 3 m)
  5. 5E (x = 4 m)
  6. 6F (x = 5 m)
  7. 7G (x = 6 m)
2.Easy
w = 2 kN/mABsection4.5 m0.5 m

The cantilever is fixed at A and carries a uniformly distributed load w over its whole length. Find the shear force Vx at the section x = 4.5 m from the fixed support A. Use sagging moments positive and upward shear on the left face positive.

L = 5 mw = 2 kN/m from 0 to 5 mx = 4.5 m
Vx = kN
3.Medium
P1​ = 55 kNP2​ = 50 kNABC1.5 m4.5 m1.5 m

The beam rests on a pin at A and a roller at B and overhangs B by 1.5 m to the free end C. It carries a point load P1 between the supports and a point load P2 at C. Find the bending moment Mx under the load P1. Use sagging moments positive and upward shear on the left face positive.

L = 7.5 mP1 = 55 kN at 1.5 mP2 = 50 kN at 7.5 msupports at x = 0 and x = 6 m
Mx = kN·m
4.Medium
w = 8 kN/mABsection2 m3 m

Find the bending moment Mx at the section x = 2 m from support A. Use sagging moments positive and upward shear on the left face positive.

L = 5 mw = 8 kN/m from 0 to 5 mx = 2 m
Mx = kN·m
5.Hard
w = 6 kN/mABC5 m1 m

The beam rests on a pin at A and a roller at B and overhangs B by 1 m to the free end C. A uniformly distributed load w acts over the whole length A–C. Find the distance xc from A to the point of contraflexure between the supports (where the bending moment changes sign).

L = 6 mw = 6 kN/m from 0 to 6 msupports at x = 0 and x = 5 m
xc = m
6.Hard
w = 3 kN/mABC8 m1.5 m

The beam rests on a pin at A and a roller at B and overhangs B by 1.5 m to the free end C. A uniformly distributed load w acts over the whole length A–C. Find the maximum sagging bending moment Mmax between the supports.

L = 9.5 mw = 3 kN/m from 0 to 9.5 msupports at x = 0 and x = 8 m
Mmax = kN·m

Answer key

  1. 1. E (x = 4 m)
  2. 2. Vx = 1 kN
  3. 3. Mx = 43.13 kN·m
  4. 4. Mx = 24 kN·m
  5. 5. xc = 4.8 m
  6. 6. Mmax = 22.34 kN·m

Full step-by-step solutions: practise this topic on examproblems.com.