Find the bending moment Mx at the section x = 2 m from support A. Use sagging moments positive and upward shear on the left face positive.
Shear force & bending moment worksheet with answers
1.Easy
L = 10 mP = 75 kN at 2 mx = 2 m
Mx = kN·m
2.Easy
The marks A to G split the beam into six equal parts. At which mark is the bending moment largest in size, sagging or hogging? Click it in the diagram.
55 kN @ 4 m
- 1A (x = 0 m)
- 2B (x = 1 m)
- 3C (x = 2 m)
- 4D (x = 3 m)
- 5E (x = 4 m)
- 6F (x = 5 m)
- 7G (x = 6 m)
3.Medium
Find the shear force Vx at the section x = 6 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 10 mw = 6 kN/m from 0 to 10 mx = 6 m
Vx = kN
4.Medium
The simply supported beam carries two point loads. Find the maximum bending moment Mmax in the beam.
L = 10 mP1 = 25 kN at 7 mP2 = 60 kN at 9 m
Mmax = kN·m
5.Hard
Find the bending moment Mx at the section x = 3 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 5 mP = 25 kN at 3 mw = 10 kN/m from 0 to 5 mx = 3 m
Mx = kN·m
6.Hard
Find the bending moment Mx at the section x = 4 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 6 mP = 35 kN at 4 mw = 4 kN/m from 0 to 6 mx = 4 m
Mx = kN·m
Answer key
- 1. Mx = 120 kN·m
- 2. E (x = 4 m)
- 3. Vx = −6 kN
- 4. Mmax = 94.5 kN·m
- 5. Mx = 60 kN·m
- 6. Mx = 62.67 kN·m
Full step-by-step solutions: practise this topic on examproblems.com.