The cantilever is fixed at A and carries a uniformly distributed load w over its whole length. Find the shear force Vx at the section x = 2.5 m from the fixed support A. Use sagging moments positive and upward shear on the left face positive.
Shear force & bending moment worksheet with answers
1.Easy
L = 3 mw = 6 kN/m from 0 to 3 mx = 2.5 m
Vx = kN
2.Easy
The marks A to G split the beam into six equal parts. At which mark is the bending moment largest in size, sagging or hogging? Click it in the diagram.
15 kN @ 1 m
- 1A (x = 0 m)
- 2B (x = 1 m)
- 3C (x = 2 m)
- 4D (x = 3 m)
- 5E (x = 4 m)
- 6F (x = 5 m)
- 7G (x = 6 m)
3.Medium
The simply supported beam carries two point loads. Find the maximum bending moment Mmax in the beam.
L = 8 mP1 = 10 kN at 2 mP2 = 40 kN at 3 m
Mmax = kN·m
4.Medium
Find the bending moment Mx at the section x = 5.5 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 6 mw = 5 kN/m from 0 to 6 mx = 5.5 m
Mx = kN·m
5.Hard
Find the bending moment Mx at the section x = 2.5 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 6 mP = 20 kN at 2.5 mw = 4 kN/m from 0 to 6 mx = 2.5 m
Mx = kN·m
6.Hard
Find the bending moment Mx at the section x = 3 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 4 mP = 10 kN at 1 mw = 6 kN/m from 0 to 4 mx = 3 m
Mx = kN·m
Answer key
- 1. Vx = 3 kN
- 2. B (x = 1 m)
- 3. Mmax = 87.5 kN·m
- 4. Mx = 6.875 kN·m
- 5. Mx = 46.67 kN·m
- 6. Mx = 11.5 kN·m
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