The cantilever is fixed at A and carries a uniformly distributed load w over its whole length. Find the bending moment Mx at the section x = 1 m from the fixed support A. Use sagging moments positive and upward shear on the left face positive.
Shear force & bending moment worksheet with answers
1.Easy
L = 2.5 mw = 10 kN/m from 0 to 2.5 mx = 1 m
Mx = kN·m
2.Easy
The marks A to G split the beam into six equal parts. At which mark is the bending moment largest in size, sagging or hogging? Click it in the diagram.
10 kN @ 3 m
- 1A (x = 0 m)
- 2B (x = 1 m)
- 3C (x = 2 m)
- 4D (x = 3 m)
- 5E (x = 4 m)
- 6F (x = 5 m)
- 7G (x = 6 m)
3.Medium
The simply supported beam carries two point loads. Find the maximum bending moment Mmax in the beam.
L = 8 mP1 = 65 kN at 1 mP2 = 55 kN at 5 m
Mmax = kN·m
4.Medium
Find the bending moment Mx at the section x = 3.5 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 6 mw = 5 kN/m from 0 to 6 mx = 3.5 m
Mx = kN·m
5.Hard
Find the bending moment Mx at the section x = 1.5 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 4 mP = 25 kN at 3 mw = 6 kN/m from 0 to 4 mx = 1.5 m
Mx = kN·m
6.Hard
Find the bending moment Mx at the section x = 5.5 m from support A. Use sagging moments positive and upward shear on the left face positive.
L = 8 mP = 55 kN at 4 mw = 5 kN/m from 0 to 8 mx = 5.5 m
Mx = kN·m
Answer key
- 1. Mx = −11.25 kN·m
- 2. D (x = 3 m)
- 3. Mmax = 127.5 kN·m
- 4. Mx = 21.88 kN·m
- 5. Mx = 20.63 kN·m
- 6. Mx = 103.1 kN·m
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