A proportional gain K controls the plant G(s) = 1/(s + 10) in a unity-feedback loop. Find the gain K that places the closed-loop pole at s = −10.5.
Stability: Routh–Hurwitz & root locus worksheet with answers
1.Easy
G(s) = 1/(s + 10)p = −10.5
K =
2.Easy
A proportional controller with gain K = 2 drives the plant G(s) = 5/(s + 5) in a unity-feedback loop. Find the closed-loop pole p.
G(s) = 5/(s + 5)K = 2
p =
3.Medium
A unity-feedback loop has L(s) = K/((s + 3)(s + 4)(s + 6)), with K > 0. Find the largest gain Kmax for which the closed loop is stable.
L(s) = K/((s + 3)(s + 4)(s + 6))
Kmax =
4.Medium
The loop in the diagram has negative feedback and L(s) = 3840/(s(s + 6)(s + 10)). How many closed-loop poles N lie in the right half-plane?
L(s) = 3840/(s(s + 6)(s + 10))
N =
5.Hard
The root locus of L(s) = K/((s + 2)(s + 8)) is shown. Find the gain K at the break-away point sb, where the two closed-loop poles meet on the real axis.
L(s) = K/((s + 2)(s + 8))
K =
6.Hard
For the loop L(s) = K/(s(s + 2)(s + 6)), find the gain K that puts a closed-loop pole at s = −0.5.
L(s) = K/(s(s + 2)(s + 6))s = −0.5
K =
Answer key
- 1. K = 0.5
- 2. p = −15
- 3. Kmax = 630
- 4. N = 2
- 5. K = 9
- 6. K = 4.125
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