The characteristic equation of a closed loop is s³ + a·s² + 3s + 9 = 0. Find the value of a above which the system is stable.
Stability: Routh–Hurwitz & root locus worksheet with answers
1.Easy
s³ + a·s² + 3s + 9 = 0
a =
2.Easy
A proportional gain K controls the plant G(s) = 5/(s + 10) in a unity-feedback loop. Find the gain K that places the closed-loop pole at s = −30.
G(s) = 5/(s + 10)p = −30
K =
3.Medium
A unity-feedback loop has L(s) = K(s + 12)/(s(s + 2)(s + 4)), with K > 0. Find the largest gain Kmax for which the closed loop is stable.
L(s) = K(s + 12)/(s(s + 2)(s + 4))
Kmax =
4.Medium
A unity-feedback loop has L(s) = K(s + 7)/(s(s + 2)(s + 3)), with K > 0. Find the largest gain Kmax for which the closed loop is stable.
L(s) = K(s + 7)/(s(s + 2)(s + 3))
Kmax =
5.Hard
For the loop L(s) = K/(s(s + 6)(s + 10)), find the gain K that puts a closed-loop pole at s = −2.
L(s) = K/(s(s + 6)(s + 10))s = −2
K =
6.Hard
For the loop L(s) = K/(s(s + 2)(s + 6)), find the gain K that puts a closed-loop pole at s = −1.5.
L(s) = K/(s(s + 2)(s + 6))s = −1.5
K =
Answer key
- 1. a = 3
- 2. K = 4
- 3. Kmax = 8
- 4. Kmax = 15
- 5. K = 64
- 6. K = 3.375
Full step-by-step solutions: practise this topic on examproblems.com.