For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 8 g of N2? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
2.Easy
For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 50 g of C6H12O6? Assume the other reactants are in excess.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
3.Medium
20 g of Fe2O3 and 24 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of CO2 can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(CO2) = 44.01 g/mol
m = g
4.Medium
10 g of Fe2O3 and 8 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
5.Hard
In the reaction C3H8 + 5O2 → 3CO2 + 4H2O, 6 g of C3H8 reacts completely (the other reactants are in excess) and 7.36 g of H2O is collected. Find the percent yield Y.
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/molactual: 7.36 g
Y = %
6.Hard
In the reaction 2Al + 3Cl2 → 2AlCl3, 30 g of Al reacts completely (the other reactants are in excess) and 111.2 g of AlCl3 is collected. Find the percent yield Y.
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/molactual: 111.2 g
Y = %
Answer key
- 1. m = 9.724 g
- 2. m = 25.57 g
- 3. m = 16.54 g
- 4. m = 6.995 g
- 5. Y = 75.05 %
- 6. Y = 75 %
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