For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 40 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
2.Easy
For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of H2O forms from 25 g of C3H8? Assume the other reactants are in excess.
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/mol
m = g
3.Medium
20 g of Na and 48 g of Cl2 react according to 2Na + Cl2 → 2NaCl. What mass m of NaCl can form?
M(Na) = 22.99M(Cl2) = 70.9M(NaCl) = 58.44 g/mol
m = g
4.Medium
30 g of CH4 and 24 g of O2 react according to CH4 + 2O2 → CO2 + 2H2O. What mass m of H2O can form?
M(CH4) = 16.04M(O2) = 32M(H2O) = 18.02 g/mol
m = g
5.Hard
In the reaction 2Mg + O2 → 2MgO, 20 g of Mg reacts completely (the other reactants are in excess) and 28.18 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 28.18 g
Y = %
6.Hard
In the reaction CH4 + 2O2 → CO2 + 2H2O, 6 g of CH4 reacts completely (the other reactants are in excess) and 14.98 g of CO2 is collected. Find the percent yield Y.
M(CH4) = 16.04 g/molM(CO2) = 44.01 g/molactual: 14.98 g
Y = %
Answer key
- 1. m = 20.46 g
- 2. m = 40.86 g
- 3. m = 50.84 g
- 4. m = 13.52 g
- 5. Y = 84.99 %
- 6. Y = 90.99 %
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