For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 8 g of N2? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
2.Easy
For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 8 g of C6H12O6? Assume the other reactants are in excess.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
3.Medium
16 g of H2 and 16 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
4.Medium
8 g of C3H8 and 20 g of O2 react according to C3H8 + 5O2 → 3CO2 + 4H2O. What mass m of H2O can form?
M(C3H8) = 44.1M(O2) = 32M(H2O) = 18.02 g/mol
m = g
5.Hard
In the reaction 2H2 + O2 → 2H2O, 16 g of H2 reacts completely (the other reactants are in excess) and 111.5 g of H2O is collected. Find the percent yield Y.
M(H2) = 2.016 g/molM(H2O) = 18.02 g/molactual: 111.5 g
Y = %
6.Hard
In the reaction C6H12O6 → 2C2H5OH + 2CO2, 12 g of C6H12O6 reacts completely (the other reactants are in excess) and 4.57 g of CO2 is collected. Find the percent yield Y.
M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/molactual: 4.57 g
Y = %
Answer key
- 1. m = 9.724 g
- 2. m = 4.091 g
- 3. m = 18.02 g
- 4. m = 9.01 g
- 5. Y = 78 %
- 6. Y = 77.95 %
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