For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of CO2 forms from 25 g of C3H8? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C3H8) = 44.1 g/molM(CO2) = 44.01 g/mol
m = g
2.Easy
For the reaction CH4 + 2O2 → CO2 + 2H2O, what mass m of H2O forms from 10 g of CH4? Assume the other reactants are in excess.
M(CH4) = 16.04 g/molM(H2O) = 18.02 g/mol
m = g
3.Medium
16 g of Fe2O3 and 32 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of CO2 can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(CO2) = 44.01 g/mol
m = g
4.Medium
24 g of C3H8 and 10 g of O2 react according to C3H8 + 5O2 → 3CO2 + 4H2O. What mass m of H2O can form?
M(C3H8) = 44.1M(O2) = 32M(H2O) = 18.02 g/mol
m = g
5.Hard
In the reaction 2Mg + O2 → 2MgO, 20 g of Mg reacts completely (the other reactants are in excess) and 27.19 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 27.19 g
Y = %
6.Hard
In the reaction 2Mg + O2 → 2MgO, 24 g of Mg reacts completely (the other reactants are in excess) and 32.62 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 32.62 g
Y = %
Answer key
- 1. m = 74.85 g
- 2. m = 22.47 g
- 3. m = 13.23 g
- 4. m = 4.505 g
- 5. Y = 82.01 %
- 6. Y = 81.99 %
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