For the reaction 2Al + 3Cl2 → 2AlCl3, what mass m of AlCl3 forms from 12 g of Al? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/mol
m = g
2.Easy
For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 100 g of C6H12O6? Assume the other reactants are in excess.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
3.Medium
20 g of H2 and 80 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
4.Medium
20 g of Al and 20 g of Cl2 react according to 2Al + 3Cl2 → 2AlCl3. What mass m of AlCl3 can form?
M(Al) = 26.98M(Cl2) = 70.9M(AlCl3) = 133.33 g/mol
m = g
5.Hard
In the reaction 2Na + Cl2 → 2NaCl, 20 g of Na reacts completely (the other reactants are in excess) and 41.69 g of NaCl is collected. Find the percent yield Y.
M(Na) = 22.99 g/molM(NaCl) = 58.44 g/molactual: 41.69 g
Y = %
6.Hard
In the reaction 2Mg + O2 → 2MgO, 24 g of Mg reacts completely (the other reactants are in excess) and 33.82 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 33.82 g
Y = %
Answer key
- 1. m = 59.3 g
- 2. m = 51.14 g
- 3. m = 90.1 g
- 4. m = 25.07 g
- 5. Y = 82 %
- 6. Y = 85 %
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