For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of H2O forms from 8 g of C3H8? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/mol
m = g
2.Easy
For the reaction 2Al + 3Cl2 → 2AlCl3, what mass m of AlCl3 forms from 5 g of Al? Assume the other reactants are in excess.
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/mol
m = g
3.Medium
10 g of Al and 40 g of Cl2 react according to 2Al + 3Cl2 → 2AlCl3. What mass m of AlCl3 can form?
M(Al) = 26.98M(Cl2) = 70.9M(AlCl3) = 133.33 g/mol
m = g
4.Medium
10 g of Na and 32 g of Cl2 react according to 2Na + Cl2 → 2NaCl. What mass m of NaCl can form?
M(Na) = 22.99M(Cl2) = 70.9M(NaCl) = 58.44 g/mol
m = g
5.Hard
In the reaction C3H8 + 5O2 → 3CO2 + 4H2O, 8 g of C3H8 reacts completely (the other reactants are in excess) and 12.29 g of H2O is collected. Find the percent yield Y.
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/molactual: 12.29 g
Y = %
6.Hard
In the reaction 2Mg + O2 → 2MgO, 8 g of Mg reacts completely (the other reactants are in excess) and 12.07 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 12.07 g
Y = %
Answer key
- 1. m = 13.08 g
- 2. m = 24.71 g
- 3. m = 49.42 g
- 4. m = 25.42 g
- 5. Y = 93.99 %
- 6. Y = 91.01 %
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