For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 12 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
2.Easy
For the reaction 2Na + Cl2 → 2NaCl, what mass m of NaCl forms from 5 g of Na? Assume the other reactants are in excess.
M(Na) = 22.99 g/molM(NaCl) = 58.44 g/mol
m = g
3.Medium
16 g of Na and 64 g of Cl2 react according to 2Na + Cl2 → 2NaCl. What mass m of NaCl can form?
M(Na) = 22.99M(Cl2) = 70.9M(NaCl) = 58.44 g/mol
m = g
4.Medium
10 g of H2 and 10 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
5.Hard
In the reaction N2 + 3H2 → 2NH3, 6 g of N2 reacts completely (the other reactants are in excess) and 5.11 g of NH3 is collected. Find the percent yield Y.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/molactual: 5.11 g
Y = %
6.Hard
In the reaction Fe2O3 + 3CO → 2Fe + 3CO2, 4 g of Fe2O3 reacts completely (the other reactants are in excess) and 2.18 g of Fe is collected. Find the percent yield Y.
M(Fe2O3) = 159.69 g/molM(Fe) = 55.85 g/molactual: 2.18 g
Y = %
Answer key
- 1. m = 6.137 g
- 2. m = 12.71 g
- 3. m = 40.67 g
- 4. m = 11.26 g
- 5. Y = 70.06 %
- 6. Y = 77.91 %
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