For the reaction 2Mg + O2 → 2MgO, what mass m of MgO forms from 10 g of Mg? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/mol
m = g
2.Easy
For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of CO2 forms from 8 g of C3H8? Assume the other reactants are in excess.
M(C3H8) = 44.1 g/molM(CO2) = 44.01 g/mol
m = g
3.Medium
30 g of H2 and 20 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
4.Medium
30 g of Mg and 80 g of O2 react according to 2Mg + O2 → 2MgO. What mass m of MgO can form?
M(Mg) = 24.31M(O2) = 32M(MgO) = 40.3 g/mol
m = g
5.Hard
In the reaction 2H2 + O2 → 2H2O, 16 g of H2 reacts completely (the other reactants are in excess) and 111.5 g of H2O is collected. Find the percent yield Y.
M(H2) = 2.016 g/molM(H2O) = 18.02 g/molactual: 111.5 g
Y = %
6.Hard
In the reaction Fe2O3 + 3CO → 2Fe + 3CO2, 8 g of Fe2O3 reacts completely (the other reactants are in excess) and 6.02 g of CO2 is collected. Find the percent yield Y.
M(Fe2O3) = 159.69 g/molM(CO2) = 44.01 g/molactual: 6.02 g
Y = %
Answer key
- 1. m = 16.58 g
- 2. m = 23.95 g
- 3. m = 22.52 g
- 4. m = 49.73 g
- 5. Y = 78 %
- 6. Y = 91.01 %
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