For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of CO2 forms from 40 g of C3H8? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C3H8) = 44.1 g/molM(CO2) = 44.01 g/mol
m = g
2.Easy
For the reaction CH4 + 2O2 → CO2 + 2H2O, what mass m of CO2 forms from 5 g of CH4? Assume the other reactants are in excess.
M(CH4) = 16.04 g/molM(CO2) = 44.01 g/mol
m = g
3.Medium
16 g of H2 and 32 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
4.Medium
16 g of Al and 24 g of Cl2 react according to 2Al + 3Cl2 → 2AlCl3. What mass m of AlCl3 can form?
M(Al) = 26.98M(Cl2) = 70.9M(AlCl3) = 133.33 g/mol
m = g
5.Hard
In the reaction 2Mg + O2 → 2MgO, 12 g of Mg reacts completely (the other reactants are in excess) and 12.33 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 12.33 g
Y = %
6.Hard
In the reaction 2Al + 3Cl2 → 2AlCl3, 20 g of Al reacts completely (the other reactants are in excess) and 84.01 g of AlCl3 is collected. Find the percent yield Y.
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/molactual: 84.01 g
Y = %
Answer key
- 1. m = 119.8 g
- 2. m = 13.72 g
- 3. m = 36.04 g
- 4. m = 30.09 g
- 5. Y = 61.98 %
- 6. Y = 85 %
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