For the reaction C3H8 + 5O2 → 3CO2 + 4H2O, what mass m of H2O forms from 8 g of C3H8? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/mol
m = g
2.Easy
For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 64 g of N2? Assume the other reactants are in excess.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
3.Medium
24 g of H2 and 48 g of O2 react according to 2H2 + O2 → 2H2O. What mass m of H2O can form?
M(H2) = 2.016M(O2) = 32M(H2O) = 18.02 g/mol
m = g
4.Medium
6 g of Na and 40 g of Cl2 react according to 2Na + Cl2 → 2NaCl. What mass m of NaCl can form?
M(Na) = 22.99M(Cl2) = 70.9M(NaCl) = 58.44 g/mol
m = g
5.Hard
In the reaction C3H8 + 5O2 → 3CO2 + 4H2O, 12 g of C3H8 reacts completely (the other reactants are in excess) and 17.26 g of H2O is collected. Find the percent yield Y.
M(C3H8) = 44.1 g/molM(H2O) = 18.02 g/molactual: 17.26 g
Y = %
6.Hard
In the reaction C6H12O6 → 2C2H5OH + 2CO2, 12 g of C6H12O6 reacts completely (the other reactants are in excess) and 3.38 g of C2H5OH is collected. Find the percent yield Y.
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/molactual: 3.38 g
Y = %
Answer key
- 1. m = 13.08 g
- 2. m = 77.8 g
- 3. m = 54.06 g
- 4. m = 15.25 g
- 5. Y = 88 %
- 6. Y = 55.07 %
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