For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 40 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
2.Easy
For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 32 g of N2? Assume the other reactants are in excess.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
3.Medium
16 g of N2 and 10 g of H2 react according to N2 + 3H2 → 2NH3. What mass m of NH3 can form?
M(N2) = 28.02M(H2) = 2.016M(NH3) = 17.03 g/mol
m = g
4.Medium
6 g of Fe2O3 and 16 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
5.Hard
In the reaction N2 + 3H2 → 2NH3, 4 g of N2 reacts completely (the other reactants are in excess) and 3.99 g of NH3 is collected. Find the percent yield Y.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/molactual: 3.99 g
Y = %
6.Hard
In the reaction CH4 + 2O2 → CO2 + 2H2O, 10 g of CH4 reacts completely (the other reactants are in excess) and 24.15 g of CO2 is collected. Find the percent yield Y.
M(CH4) = 16.04 g/molM(CO2) = 44.01 g/molactual: 24.15 g
Y = %
Answer key
- 1. m = 19.54 g
- 2. m = 38.9 g
- 3. m = 19.45 g
- 4. m = 4.197 g
- 5. Y = 82.06 %
- 6. Y = 88.02 %
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