For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of C2H5OH forms from 40 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(C2H5OH) = 46.07 g/mol
m = g
2.Easy
For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 25 g of C6H12O6? Assume the other reactants are in excess.
M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
3.Medium
30 g of Mg and 24 g of O2 react according to 2Mg + O2 → 2MgO. What mass m of MgO can form?
M(Mg) = 24.31M(O2) = 32M(MgO) = 40.3 g/mol
m = g
4.Medium
20 g of CH4 and 20 g of O2 react according to CH4 + 2O2 → CO2 + 2H2O. What mass m of CO2 can form?
M(CH4) = 16.04M(O2) = 32M(CO2) = 44.01 g/mol
m = g
5.Hard
In the reaction CaCO3 → CaO + CO2, 30 g of CaCO3 reacts completely (the other reactants are in excess) and 10.82 g of CO2 is collected. Find the percent yield Y.
M(CaCO3) = 100.09 g/molM(CO2) = 44.01 g/molactual: 10.82 g
Y = %
6.Hard
In the reaction N2 + 3H2 → 2NH3, 12 g of N2 reacts completely (the other reactants are in excess) and 10.94 g of NH3 is collected. Find the percent yield Y.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/molactual: 10.94 g
Y = %
Answer key
- 1. m = 20.46 g
- 2. m = 12.21 g
- 3. m = 49.73 g
- 4. m = 13.75 g
- 5. Y = 82.02 %
- 6. Y = 75 %
Full step-by-step solutions: practise this topic on examproblems.com.