For the reaction 2Al + 3Cl2 → 2AlCl3, what mass m of AlCl3 forms from 32 g of Al? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(Al) = 26.98 g/molM(AlCl3) = 133.33 g/mol
m = g
2.Easy
For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 5 g of N2? Assume the other reactants are in excess.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
3.Medium
12 g of Na and 10 g of Cl2 react according to 2Na + Cl2 → 2NaCl. What mass m of NaCl can form?
M(Na) = 22.99M(Cl2) = 70.9M(NaCl) = 58.44 g/mol
m = g
4.Medium
30 g of Fe2O3 and 80 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
5.Hard
In the reaction 2Na + Cl2 → 2NaCl, 30 g of Na reacts completely (the other reactants are in excess) and 57.19 g of NaCl is collected. Find the percent yield Y.
M(Na) = 22.99 g/molM(NaCl) = 58.44 g/molactual: 57.19 g
Y = %
6.Hard
In the reaction 2Mg + O2 → 2MgO, 12 g of Mg reacts completely (the other reactants are in excess) and 12.33 g of MgO is collected. Find the percent yield Y.
M(Mg) = 24.31 g/molM(MgO) = 40.3 g/molactual: 12.33 g
Y = %
Answer key
- 1. m = 158.1 g
- 2. m = 6.078 g
- 3. m = 16.49 g
- 4. m = 20.98 g
- 5. Y = 74.99 %
- 6. Y = 61.98 %
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