For the reaction C6H12O6 → 2C2H5OH + 2CO2, what mass m of CO2 forms from 100 g of C6H12O6? Assume the other reactants are in excess.
Stoichiometry worksheet with answers
1.Easy
M(C6H12O6) = 180.16 g/molM(CO2) = 44.01 g/mol
m = g
2.Easy
For the reaction N2 + 3H2 → 2NH3, what mass m of NH3 forms from 32 g of N2? Assume the other reactants are in excess.
M(N2) = 28.02 g/molM(NH3) = 17.03 g/mol
m = g
3.Medium
20 g of Fe2O3 and 20 g of CO react according to Fe2O3 + 3CO → 2Fe + 3CO2. What mass m of Fe can form?
M(Fe2O3) = 159.69M(CO) = 28.01M(Fe) = 55.85 g/mol
m = g
4.Medium
10 g of Al and 48 g of Cl2 react according to 2Al + 3Cl2 → 2AlCl3. What mass m of AlCl3 can form?
M(Al) = 26.98M(Cl2) = 70.9M(AlCl3) = 133.33 g/mol
m = g
5.Hard
In the reaction C3H8 + 5O2 → 3CO2 + 4H2O, 16 g of C3H8 reacts completely (the other reactants are in excess) and 43.59 g of CO2 is collected. Find the percent yield Y.
M(C3H8) = 44.1 g/molM(CO2) = 44.01 g/molactual: 43.59 g
Y = %
6.Hard
In the reaction CaCO3 → CaO + CO2, 8 g of CaCO3 reacts completely (the other reactants are in excess) and 3.14 g of CaO is collected. Find the percent yield Y.
M(CaCO3) = 100.09 g/molM(CaO) = 56.08 g/molactual: 3.14 g
Y = %
Answer key
- 1. m = 48.86 g
- 2. m = 38.9 g
- 3. m = 13.99 g
- 4. m = 49.42 g
- 5. Y = 91 %
- 6. Y = 70.05 %
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