Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the contribution I_R2′ of V₁ alone to the current I_R2 through R₂ in the direction of the arrow.

V₁ = 8 VV₂ = 6 VR₁ = 5 ΩR₂ = 3 ΩR₃ = 5 Ω

I_R2′ = A

2.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 6 VV₂ = 24 VR₁ = 8 ΩR₂ = 6 ΩR₃ = 5 Ω

I_R2 = A

3.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 18 VR₁ = 8 ΩR₂ = 5 ΩR₃ = 4 ΩR₄ = 2 Ω

I_s = A

4.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 4 V and I_s = 8 mA, I = 12.8 mA; with V_s = 10 V and I_s = 10 mA, I = 26 mA. Find the load current I when V_s = 2 V and I_s = 2 mA.

4 V, 8 mA → 12.8 mA10 V, 10 mA → 26 mAV_s = 2 V, I_s = 2 mA

I = mA

5.Hard

Find the value of the voltage source V₂ (polarity as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 5 VI_s = 2 AR₁ = 10 ΩR₂ = 6 ΩR₃ = 8 ΩR₄ = 10 Ω

V₂ = V

6.Hard

Use superposition to find the current I_R4 through R₄ in the direction of the arrow.

V₁ = 24 VI_s = 4 AV₂ = 9 VR₁ = 12 ΩR₂ = 4 ΩR₃ = 2 ΩR₄ = 4 Ω

I_R4 = A

Answer key

1. I_R2′ = 0.7273 A
2. I_R2 = −2.39 A
3. I_s = 3.462 A
4. I = 5.2 mA
5. V₂ = 12 V
6. I_R4 = −2.926 A

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