Use superposition to find the contribution IR2′ of V1 alone to the current IR2 through R2 in the direction of the arrow.
Superposition worksheet with answers
1.Easy
V1 = 15 VV2 = 15 VR1 = 3 ΩR2 = 8 ΩR3 = 12 Ω
IR2′ = A
2.Easy
Use superposition to find the current IR2 through R2 in the direction of the arrow.
V1 = 10 VIs = 2 AR1 = 2 ΩR2 = 10 Ω
IR2 = A
3.Medium
Use superposition to find the current IR3 through R3 in the direction of the arrow.
V1 = 6 VIs = 1.5 AR1 = 10 ΩR2 = 5 ΩR3 = 3 ΩR4 = 5 Ω
IR3 = A
4.Medium
Use superposition to find the voltage VR4 across R4 with the polarity shown.
V1 = 10 VIs = 2 AR1 = 12 ΩR2 = 10 ΩR3 = 8 ΩR4 = 15 Ω
VR4 = V
5.Hard
Use superposition to find the current IR4 through R4 in the direction of the arrow.
V1 = 12 VIs = 2 AV2 = 15 VR1 = 5 ΩR2 = 25 ΩR3 = 25 ΩR4 = 20 Ω
IR4 = A
6.Hard
Use superposition to find the voltage VR3 across R3 with the polarity shown.
V1 = 10 VIs = 0.5 AV2 = 6 VR1 = 4 ΩR2 = 6 ΩR3 = 15 ΩR4 = 12 Ω
VR3 = V
Answer key
- 1. IR2′ = 1.154 A
- 2. IR2 = 1.167 A
- 3. IR3 = 0.8382 A
- 4. VR4 = 16.58 V
- 5. IR4 = 1.085 A
- 6. VR3 = −8.507 V
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