Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
linear circuitV1​ = 24 VV2​ = 15 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 24 V and V2 = 15 V. With both sources on, the current through the load resistor is I = −12.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 6.5 mA. Find the load current I when V1 is raised to 48 V and V2 stays at 15 V.

I = −12.5 mA (both sources)I = 6.5 mA (only V1)
I = mA
2.Easy
R1​ = 6 ΩIR1​R2​ = 3 Ω+−V1​12 VR3​12 ΩA+−V2​18 V

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 12 VV2 = 18 VR1 = 6 ΩR2 = 3 ΩR3 = 12 Ω
IR1 = A
3.Medium
R1​ = 4 ΩR3​ = 20 Ω+−V1​24 VR2​4 Ω−+VR2​AR4​6 ΩBIs​1.5 A

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 24 VIs = 1.5 AR1 = 4 ΩR2 = 4 ΩR3 = 20 ΩR4 = 6 Ω
VR2 = V
4.Medium
R1​ = 20 ΩR3​ = 4 Ω+−V1​15 VR2​3 ΩIR2​AR4​12 ΩBIs​1 A

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 15 VIs = 1 AR1 = 20 ΩR2 = 3 ΩR3 = 4 ΩR4 = 12 Ω
IR2 = A
5.Hard
R1​ = 25 ΩR2​ = 8 ΩR4​ = 10 Ω+−V1​6 VR3​20 ΩIR3​AIs​2.5 AB+−V2​?

Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.

V1 = 6 VIs = 2.5 AR1 = 25 ΩR2 = 8 ΩR3 = 20 ΩR4 = 10 Ω
V2 = V
6.Hard
linear circuitV1​V2​Is​IRL​

A linear resistive circuit contains three independent sources: V1, V2 and Is. The current I through a load is measured three times. With all sources at their normal values, I = 16 mA. With V1 doubled and the other two unchanged, I = 23.5 mA. With the direction of Is reversed and the other two unchanged, I = 6 mA. Find the load current I when V2 is switched off and V1 and Is have their normal values.

normal: I = 16 mA2·V1: I = 23.5 mA−Is: I = 6 mA
I = mA

Answer key

  1. 1. I = −6 mA
  2. 2. IR1 = −0.2857 A
  3. 3. VR2 = −11.79 V
  4. 4. IR2 = 1.121 A
  5. 5. V2 = 20.68 V
  6. 6. I = 12.5 mA

Full step-by-step solutions: practise this topic on examproblems.com.