Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 12 ΩIR1​+−V1​8 VR2​12 ΩAIs​3 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 8 VIs = 3 AR1 = 12 ΩR2 = 12 Ω
IR1 = A
2.Easy
linear circuitV1​ = 20 VV2​ = 6 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 20 V and V2 = 6 V. With both sources on, the current through the load resistor is I = 25.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 18.5 mA. Find the load current I when V1 is raised to 40 V and V2 stays at 6 V.

I = 25.5 mA (both sources)I = 18.5 mA (only V1)
I = mA
3.Medium
R1​ = 6 ΩR3​ = 5 Ω+−V1​10 VR2​12 ΩAR4​4 ΩIR4​BIs​1.5 A

Use superposition to find the power PR4 absorbed by R4.

V1 = 10 VIs = 1.5 AR1 = 6 ΩR2 = 12 ΩR3 = 5 ΩR4 = 4 Ω
PR4 = W
4.Medium
R1​ = 10 ΩR3​ = 6 Ω+−V1​30 VR2​10 ΩIR2​AR4​12 ΩBIs​2 A

Use superposition to find the power PR2 absorbed by R2.

V1 = 30 VIs = 2 AR1 = 10 ΩR2 = 10 ΩR3 = 6 ΩR4 = 12 Ω
PR2 = W
5.Hard
R1​ = 15 ΩR2​ = 15 Ω+−VR2​R4​ = 3 Ω+−V1​18 VR3​6 ΩAIs​1.5 AB+−V2​15 V

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 18 VIs = 1.5 AV2 = 15 VR1 = 15 ΩR2 = 15 ΩR3 = 6 ΩR4 = 3 Ω
VR2 = V
6.Hard
R1​ = 2 ΩR2​ = 12 ΩR4​ = 15 Ω+−V1​18 VR3​3 ΩIR3​AIs​1 AB+−V2​5 V

Use superposition to find the power PR3 absorbed by R3.

V1 = 18 VIs = 1 AV2 = 5 VR1 = 2 ΩR2 = 12 ΩR3 = 3 ΩR4 = 15 Ω
PR3 = W

Answer key

  1. 1. IR1 = −1.167 A
  2. 2. I = 44 mA
  3. 3. PR4 = 9.626 W
  4. 4. PR2 = 28.75 W
  5. 5. VR2 = −9.663 V
  6. 6. PR3 = 41.75 W

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