Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
R1​ = 5 ΩIR1​+−V1​24 VR2​6 ΩAIs​1 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 24 VIs = 1 AR1 = 5 ΩR2 = 6 Ω
IR1 = A
2.Easy
R1​ = 12 ΩR2​ = 2 Ω+−V1​12 VR3​5 Ω+−VR3​A+−V2​6 V

Use superposition to find the voltage VR3 across R3 with the polarity shown.

V1 = 12 VV2 = 6 VR1 = 12 ΩR2 = 2 ΩR3 = 5 Ω
VR3 = V
3.Medium
R1​ = 3 ΩR3​ = 8 ΩIR3​+−V1​9 VR2​6 ΩAR4​20 ΩBIs​?

Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.

V1 = 9 VR1 = 3 ΩR2 = 6 ΩR3 = 8 ΩR4 = 20 Ω
Is = A
4.Medium
R1​ = 3 ΩR3​ = 5 Ω+−V1​10 VR2​10 ΩIR2​AR4​3 ΩBIs​2.5 A

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 10 VIs = 2.5 AR1 = 3 ΩR2 = 10 ΩR3 = 5 ΩR4 = 3 Ω
IR2 = A
5.Hard
linear circuitV1​V2​Is​IRL​

A linear resistive circuit contains three independent sources: V1, V2 and Is. The current I through a load is measured three times. With all sources at their normal values, I = 8 mA. With V1 doubled and the other two unchanged, I = 0.5 mA. With the direction of Is reversed and the other two unchanged, I = −4 mA. Find the load current I when V2 is switched off and V1 and Is have their normal values.

normal: I = 8 mA2·V1: I = 0.5 mA−Is: I = −4 mA
I = mA
6.Hard
R1​ = 8 ΩR2​ = 30 Ω+−VR2​R4​ = 2 Ω+−V1​30 VR3​4 ΩAIs​2.5 AB−+V2​15 V

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 30 VIs = 2.5 AV2 = 15 VR1 = 8 ΩR2 = 30 ΩR3 = 4 ΩR4 = 2 Ω
VR2 = V

Answer key

  1. 1. IR1 = 2.727 A
  2. 2. VR3 = 5.106 V
  3. 3. Is = 0.3 A
  4. 4. IR2 = 0.7649 A
  5. 5. I = −1.5 mA
  6. 6. VR2 = 25.96 V

Full step-by-step solutions: practise this topic on examproblems.com.