Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 4 Ω+−V1​15 VR2​4 ΩIR2​AIs​3 A

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 15 VIs = 3 AR1 = 4 ΩR2 = 4 Ω
IR2 = A
2.Easy
linear circuitV1​ = 15 VV2​ = 10 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 15 V and V2 = 10 V. With both sources on, the current through the load resistor is I = 20.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 14.5 mA. Find the load current I when V1 is switched off and only V2 = 10 V is active.

I = 20.5 mA (both sources)I = 14.5 mA (only V1)
I = mA
3.Medium
R1​ = 4 ΩR3​ = 12 Ω+−V1​12 VR2​8 Ω+−VR2​AR4​10 ΩBIs​3 A

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 12 VIs = 3 AR1 = 4 ΩR2 = 8 ΩR3 = 12 ΩR4 = 10 Ω
VR2 = V
4.Medium
R1​ = 5 ΩR3​ = 3 ΩIR3​+−V1​9 VR2​3 ΩAR4​10 ΩBIs​?

Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.

V1 = 9 VR1 = 5 ΩR2 = 3 ΩR3 = 3 ΩR4 = 10 Ω
Is = A
5.Hard
R1​ = 12 ΩR2​ = 8 ΩIR2​R4​ = 12 Ω+−V1​15 VR3​5 ΩAIs​1.5 AB−+V2​6 V

Use superposition to find the power PR2 absorbed by R2.

V1 = 15 VIs = 1.5 AV2 = 6 VR1 = 12 ΩR2 = 8 ΩR3 = 5 ΩR4 = 12 Ω
PR2 = W
6.Hard
R1​ = 10 ΩR2​ = 25 ΩR4​ = 5 ΩIR4​+−V1​30 VR3​10 ΩAIs​3 AB−+V2​36 V

Use superposition to find the current IR4 through R4 in the direction of the arrow.

V1 = 30 VIs = 3 AV2 = 36 VR1 = 10 ΩR2 = 25 ΩR3 = 10 ΩR4 = 5 Ω
IR4 = A

Answer key

  1. 1. IR2 = 3.375 A
  2. 2. I = 6 mA
  3. 3. VR2 = 10.38 V
  4. 4. Is = 0.3375 A
  5. 5. PR2 = 0.8321 W
  6. 6. IR4 = −4.029 A

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