Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the current I_R1 through R₁ in the direction of the arrow.

V₁ = 6 VV₂ = 24 VR₁ = 10 ΩR₂ = 2 ΩR₃ = 12 Ω

I_R1 = A

2.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 10 VV₂ = 12 VR₁ = 4 ΩR₂ = 6 ΩR₃ = 12 Ω

I_R2 = A

3.Medium

Use superposition to find the power P_R3 absorbed by R₃.

V₁ = 24 VI_s = 1.5 AR₁ = 15 ΩR₂ = 20 ΩR₃ = 5 ΩR₄ = 6 Ω

P_R3 = W

4.Medium

A linear resistive circuit contains one voltage source V_s and one current source I_s. The current I through a load resistor is measured twice: with V_s = 10 V and I_s = 10 mA, I = 19 mA; with V_s = 12 V and I_s = 1 mA, I = 18.4 mA. Find the load current I when V_s = 6 V and I_s = 6 mA.

10 V, 10 mA → 19 mA12 V, 1 mA → 18.4 mAV_s = 6 V, I_s = 6 mA

I = mA

5.Hard

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 5 VI_s = 5 AV₂ = 15 VR₁ = 10 ΩR₂ = 8 ΩR₃ = 5 ΩR₄ = 3 Ω

V_R3 = V

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 27.5 mA. With V₁ doubled and the other two unchanged, I = 35 mA. With the direction of I_s reversed and the other two unchanged, I = 8.5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 27.5 mA2·V₁: I = 35 mA−I_s: I = 8.5 mA

I = mA

Answer key

1. I_R1 = −1.244 A
2. I_R2 = −0.5 A
3. P_R3 = 6.735 W
4. I = 11.4 mA
5. V_R3 = 1.279 V
6. I = 17 mA

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