Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 3 ΩR2​ = 3 ΩIR2​+−V1​20 VR3​5 ΩA+−V2​24 V

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 20 VV2 = 24 VR1 = 3 ΩR2 = 3 ΩR3 = 5 Ω
IR2 = A
2.Easy
linear circuitV1​ = 10 VV2​ = 6 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 10 V and V2 = 6 V. With both sources on, the current through the load resistor is I = 26.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 15 mA. Find the load current I when V1 is raised to 20 V and V2 stays at 6 V.

I = 26.5 mA (both sources)I = 15 mA (only V1)
I = mA
3.Medium
R1​ = 4 ΩR3​ = 5 Ω+−V1​18 VR2​15 ΩAR4​20 Ω−+VR4​BIs​1 A

Use superposition to find the voltage VR4 across R4 with the polarity shown.

V1 = 18 VIs = 1 AR1 = 4 ΩR2 = 15 ΩR3 = 5 ΩR4 = 20 Ω
VR4 = V
4.Medium
R1​ = 4 ΩR3​ = 20 Ω+−V1​10 VR2​4 ΩIR2​AR4​5 ΩBIs​4 A

Use superposition to find the power PR2 absorbed by R2.

V1 = 10 VIs = 4 AR1 = 4 ΩR2 = 4 ΩR3 = 20 ΩR4 = 5 Ω
PR2 = W
5.Hard
R1​ = 10 ΩR2​ = 6 ΩR4​ = 10 ΩIR4​+−V1​6 VR3​30 ΩAIs​0.5 AB+−V2​9 V

Use superposition to find the power PR4 absorbed by R4.

V1 = 6 VIs = 0.5 AV2 = 9 VR1 = 10 ΩR2 = 6 ΩR3 = 30 ΩR4 = 10 Ω
PR4 = W
6.Hard
R1​ = 2 ΩR2​ = 10 Ω+−VR2​R4​ = 15 Ω+−V1​12 VR3​6 ΩAIs​2.5 AB+−V2​12 V

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 12 VIs = 2.5 AV2 = 12 VR1 = 2 ΩR2 = 10 ΩR3 = 6 ΩR4 = 15 Ω
VR2 = V

Answer key

  1. 1. IR2 = −2.359 A
  2. 2. I = 41.5 mA
  3. 3. VR4 = −15.89 V
  4. 4. PR2 = 9.336 W
  5. 5. PR4 = 2.292 W
  6. 6. VR2 = −15.28 V

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