Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the contribution I_R2″ of V₂ alone to the current I_R2 through R₂ in the direction of the arrow.

V₁ = 15 VV₂ = 6 VR₁ = 8 ΩR₂ = 4 ΩR₃ = 12 Ω

I_R2″ = A

2.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 8 VI_s = 3 AR₁ = 4 ΩR₂ = 8 Ω

I_R2 = A

3.Medium

Use superposition to find the power P_R3 absorbed by R₃.

V₁ = 18 VI_s = 3 AR₁ = 2 ΩR₂ = 3 ΩR₃ = 4 ΩR₄ = 8 Ω

P_R3 = W

4.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 24 VR₁ = 10 ΩR₂ = 6 ΩR₃ = 5 ΩR₄ = 8 Ω

I_s = A

5.Hard

Use superposition to find the power P_R1 absorbed by R₁.

V₁ = 5 VI_s = 6 AV₂ = 18 VR₁ = 6 ΩR₂ = 5 ΩR₃ = 12 ΩR₄ = 3 Ω

P_R1 = W

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 18.5 mA. With V₁ doubled and the other two unchanged, I = 23 mA. With the direction of I_s reversed and the other two unchanged, I = 3.5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 18.5 mA2·V₁: I = 23 mA−I_s: I = 3.5 mA

I = mA

Answer key

1. I_R2″ = −0.6818 A
2. I_R2 = −0.3333 A
3. P_R3 = 4 W
4. I_s = 1.125 A
5. P_R1 = 1.286 W
6. I = 12 mA

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