Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 8 VI_s = 2 AR₁ = 8 ΩR₂ = 2 Ω

I_R2 = A

2.Easy

A linear resistive circuit contains two independent voltage sources, V₁ = 24 V and V₂ = 15 V. With both sources on, the current through the load resistor is I = 25 mA. With V₂ switched off (replaced by a short circuit) and V₁ unchanged, the load current is 16.5 mA. Find the load current I when V₁ is switched off and only V₂ = 15 V is active.

I = 25 mA (both sources)I = 16.5 mA (only V₁)

I = mA

3.Medium

Use superposition to find the power P_R1 absorbed by R₁.

V₁ = 12 VI_s = 2 AR₁ = 5 ΩR₂ = 3 ΩR₃ = 12 ΩR₄ = 4 Ω

P_R1 = W

4.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 18 VR₁ = 3 ΩR₂ = 6 ΩR₃ = 6 ΩR₄ = 15 Ω

I_s = A

5.Hard

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 12 VI_s = 0.5 AV₂ = 10 VR₁ = 2 ΩR₂ = 6 ΩR₃ = 10 ΩR₄ = 3 Ω

I_R3 = A

6.Hard

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 36 VI_s = 6 AV₂ = 10 VR₁ = 5 ΩR₂ = 25 ΩR₃ = 30 ΩR₄ = 12 Ω

V_R3 = V

Answer key

1. I_R2 = 2.4 A
2. I = 8.5 mA
3. P_R1 = 15.53 W
4. I_s = 0.8 A
5. I_R3 = −1.023 A
6. V_R3 = 36.17 V

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