Use superposition to find the contribution IR2′ of V1 alone to the current IR2 through R2 in the direction of the arrow.
Superposition worksheet with answers
1.Easy
V1 = 18 VV2 = 24 VR1 = 8 ΩR2 = 4 ΩR3 = 6 Ω
IR2′ = A
2.Easy
Use superposition to find the current IR3 through R3 in the direction of the arrow.
V1 = 20 VV2 = 6 VR1 = 8 ΩR2 = 6 ΩR3 = 5 Ω
IR3 = A
3.Medium
Use superposition to find the voltage VR4 across R4 with the polarity shown.
V1 = 12 VIs = 2 AR1 = 20 ΩR2 = 12 ΩR3 = 4 ΩR4 = 15 Ω
VR4 = V
4.Medium
Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.
V1 = 10 VR1 = 8 ΩR2 = 4 ΩR3 = 5 ΩR4 = 2 Ω
Is = A
5.Hard
Use superposition to find the current IR4 through R4 in the direction of the arrow.
V1 = 12 VIs = 0.5 AV2 = 36 VR1 = 10 ΩR2 = 8 ΩR3 = 12 ΩR4 = 2 Ω
IR4 = A
6.Hard
Use superposition to find the power PR2 absorbed by R2.
V1 = 15 VIs = 6 AV2 = 9 VR1 = 30 ΩR2 = 12 ΩR3 = 3 ΩR4 = 4 Ω
PR2 = W
Answer key
- 1. IR2′ = 1.038 A
- 2. IR3 = 1.424 A
- 3. VR4 = −10.47 V
- 4. Is = 1.667 A
- 5. IR4 = 1.471 A
- 6. PR2 = 34.25 W
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