Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 8 ΩIR1​R2​ = 5 Ω+−V1​15 VR3​10 ΩA+−V2​12 V

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 15 VV2 = 12 VR1 = 8 ΩR2 = 5 ΩR3 = 10 Ω
IR1 = A
2.Easy
linear circuitV1​ = 12 VV2​ = 9 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 12 V and V2 = 9 V. With both sources on, the current through the load resistor is I = 21.5 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 2.5 mA. Find the load current I when V1 is switched off and only V2 = 9 V is active.

I = 21.5 mA (both sources)I = 2.5 mA (only V1)
I = mA
3.Medium
R1​ = 5 ΩR3​ = 15 Ω+−V1​9 VR2​10 ΩAR4​8 ΩIR4​BIs​2.5 A

Use superposition to find the power PR4 absorbed by R4.

V1 = 9 VIs = 2.5 AR1 = 5 ΩR2 = 10 ΩR3 = 15 ΩR4 = 8 Ω
PR4 = W
4.Medium
R1​ = 8 ΩR3​ = 12 Ω+−V1​9 VR2​4 ΩAR4​10 Ω−+VR4​BIs​1.5 A

Use superposition to find the voltage VR4 across R4 with the polarity shown.

V1 = 9 VIs = 1.5 AR1 = 8 ΩR2 = 4 ΩR3 = 12 ΩR4 = 10 Ω
VR4 = V
5.Hard
R1​ = 8 ΩR2​ = 5 ΩR4​ = 10 Ω+−V1​5 VR3​3 ΩIR3​AIs​5 AB+−V2​9 V

Use superposition to find the current IR3 through R3 in the direction of the arrow.

V1 = 5 VIs = 5 AV2 = 9 VR1 = 8 ΩR2 = 5 ΩR3 = 3 ΩR4 = 10 Ω
IR3 = A
6.Hard
R1​ = 15 ΩR2​ = 6 ΩIR2​R4​ = 4 Ω+−V1​6 VR3​2 ΩAIs​4 AB−+V2​5 V

Use superposition to find the power PR2 absorbed by R2.

V1 = 6 VIs = 4 AV2 = 5 VR1 = 15 ΩR2 = 6 ΩR3 = 2 ΩR4 = 4 Ω
PR2 = W

Answer key

  1. 1. IR1 = 0.6176 A
  2. 2. I = 19 mA
  3. 3. PR4 = 31 W
  4. 4. VR4 = −10.14 V
  5. 5. IR3 = −2.894 A
  6. 6. PR2 = 4.594 W

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