Use superposition to find the contribution VR3′ of V1 alone to the voltage VR3 across R3 with the polarity shown.
Superposition worksheet with answers
1.Easy
V1 = 20 VV2 = 12 VR1 = 2 ΩR2 = 3 ΩR3 = 8 Ω
VR3′ = V
2.Easy
Use superposition to find the contribution IR3′ of V1 alone to the current IR3 through R3 in the direction of the arrow.
V1 = 24 VV2 = 15 VR1 = 10 ΩR2 = 10 ΩR3 = 8 Ω
IR3′ = A
3.Medium
Use superposition to find the current IR1 through R1 in the direction of the arrow.
V1 = 18 VIs = 1 AR1 = 2 ΩR2 = 20 ΩR3 = 20 ΩR4 = 20 Ω
IR1 = A
4.Medium
Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.
V1 = 30 VR1 = 6 ΩR2 = 20 ΩR3 = 5 ΩR4 = 10 Ω
Is = A
5.Hard
Use superposition to find the current IR2 through R2 in the direction of the arrow.
V1 = 10 VIs = 4 AV2 = 9 VR1 = 5 ΩR2 = 12 ΩR3 = 8 ΩR4 = 12 Ω
IR2 = A
6.Hard
Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.
V1 = 6 VIs = 2.5 AR1 = 8 ΩR2 = 5 ΩR3 = 30 ΩR4 = 6 Ω
V2 = V
Answer key
- 1. VR3′ = 10.43 V
- 2. IR3′ = 0.9231 A
- 3. IR1 = 0.7391 A
- 4. Is = 2.308 A
- 5. IR2 = −1.878 A
- 6. V2 = 6.75 V
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