Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 6 VV₂ = 12 VR₁ = 12 ΩR₂ = 10 ΩR₃ = 8 Ω

I_R3 = A

2.Easy

Use superposition to find the current I_R1 through R₁ in the direction of the arrow.

V₁ = 15 VI_s = 3 AR₁ = 6 ΩR₂ = 6 Ω

I_R1 = A

3.Medium

Use superposition to find the voltage V_R2 across R₂ with the polarity shown.

V₁ = 6 VI_s = 1 AR₁ = 4 ΩR₂ = 20 ΩR₃ = 6 ΩR₄ = 15 Ω

V_R2 = V

4.Medium

Use superposition to find the power P_R3 absorbed by R₃.

V₁ = 30 VI_s = 1 AR₁ = 20 ΩR₂ = 8 ΩR₃ = 8 ΩR₄ = 6 Ω

P_R3 = W

5.Hard

Use superposition to find the power P_R4 absorbed by R₄.

V₁ = 10 VI_s = 0.5 AV₂ = 30 VR₁ = 12 ΩR₂ = 4 ΩR₃ = 8 ΩR₄ = 6 Ω

P_R4 = W

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 11 mA. With V₁ doubled and the other two unchanged, I = 9 mA. With the direction of I_s reversed and the other two unchanged, I = −11 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 11 mA2·V₁: I = 9 mA−I_s: I = −11 mA

I = mA

Answer key

1. I_R3 = 0.6892 A
2. I_R1 = 2.75 A
3. V_R2 = 6.37 V
4. P_R3 = 4.371 W
5. P_R4 = 40.39 W
6. I = 9 mA

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