Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the node voltage V_A (measured from ground).

V₁ = 20 VI_s = 3 AR₁ = 8 ΩR₂ = 4 Ω

V_A = V

2.Easy

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 24 VV₂ = 24 VR₁ = 4 ΩR₂ = 4 ΩR₃ = 2 Ω

V_R3 = V

3.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 18 VR₁ = 8 ΩR₂ = 20 ΩR₃ = 3 ΩR₄ = 12 Ω

I_s = A

4.Medium

Use superposition to find the voltage V_R4 across R₄ with the polarity shown.

V₁ = 6 VI_s = 1.5 AR₁ = 6 ΩR₂ = 15 ΩR₃ = 5 ΩR₄ = 15 Ω

V_R4 = V

5.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 20.5 mA. With V₁ doubled and the other two unchanged, I = 31 mA. With the direction of I_s reversed and the other two unchanged, I = 2.5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 20.5 mA2·V₁: I = 31 mA−I_s: I = 2.5 mA

I = mA

6.Hard

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 24 VI_s = 0.5 AV₂ = 6 VR₁ = 15 ΩR₂ = 8 ΩR₃ = 10 ΩR₄ = 10 Ω

I_R3 = A

Answer key

1. V_A = 14.67 V
2. V_R3 = 12 V
3. I_s = 1.071 A
4. V_R4 = −5.956 V
5. I = 19.5 mA
6. I_R3 = 0.995 A

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