Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
R1​ = 6 ΩIR1​+−V1​12 VR2​6 ΩAIs​3 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 12 VIs = 3 AR1 = 6 ΩR2 = 6 Ω
IR1 = A
2.Easy
R1​ = 2 ΩR2​ = 10 Ω+−V1​18 VR3​4 ΩIR3​A+−V2​12 V

Use superposition to find the contribution IR3″ of V2 alone to the current IR3 through R3 in the direction of the arrow.

V1 = 18 VV2 = 12 VR1 = 2 ΩR2 = 10 ΩR3 = 4 Ω
IR3″ = A
3.Medium
R1​ = 2 ΩR3​ = 2 Ω+−V1​12 VR2​10 ΩAR4​15 ΩIR4​BIs​1.5 A

Use superposition to find the power PR4 absorbed by R4.

V1 = 12 VIs = 1.5 AR1 = 2 ΩR2 = 10 ΩR3 = 2 ΩR4 = 15 Ω
PR4 = W
4.Medium
R1​ = 15 ΩR3​ = 8 ΩIR3​+−V1​9 VR2​5 ΩAR4​5 ΩBIs​2.5 A

Use superposition to find the current IR3 through R3 in the direction of the arrow.

V1 = 9 VIs = 2.5 AR1 = 15 ΩR2 = 5 ΩR3 = 8 ΩR4 = 5 Ω
IR3 = A
5.Hard
R1​ = 12 ΩR2​ = 8 ΩR4​ = 25 Ω+−V1​5 VR3​15 ΩIR3​AIs​2.5 AB+−V2​?

Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.

V1 = 5 VIs = 2.5 AR1 = 12 ΩR2 = 8 ΩR3 = 15 ΩR4 = 25 Ω
V2 = V
6.Hard
linear circuitV1​V2​Is​IRL​

A linear resistive circuit contains three independent sources: V1, V2 and Is. The current I through a load is measured three times. With all sources at their normal values, I = 3.5 mA. With V1 doubled and the other two unchanged, I = 5.5 mA. With the direction of Is reversed and the other two unchanged, I = 21.5 mA. Find the load current I when V2 is switched off and V1 and Is have their normal values.

normal: I = 3.5 mA2·V1: I = 5.5 mA−Is: I = 21.5 mA
I = mA

Answer key

  1. 1. IR1 = −0.5 A
  2. 2. IR3″ = 0.3529 A
  3. 3. PR4 = 10.34 W
  4. 4. IR3 = 0.8806 A
  5. 5. V2 = 48.75 V
  6. 6. I = −7 mA

Full step-by-step solutions: practise this topic on examproblems.com.