Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 12 ΩR2​ = 2 Ω+−V1​6 VR3​4 ΩIR3​A+−V2​6 V

Use superposition to find the current IR3 through R3 in the direction of the arrow.

V1 = 6 VV2 = 6 VR1 = 12 ΩR2 = 2 ΩR3 = 4 Ω
IR3 = A
2.Easy
R1​ = 8 Ω+−V1​6 VR2​12 ΩAIs​3 A

Use superposition to find the node voltage VA (measured from ground).

V1 = 6 VIs = 3 AR1 = 8 ΩR2 = 12 Ω
VA = V
3.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 5 V and Is = 5 mA, I = 2 mA; with Vs = 6 V and Is = 4 mA, I = 2.8 mA. Find the load current I when Vs = 8 V and Is = 10 mA.

5 V, 5 mA → 2 mA6 V, 4 mA → 2.8 mAVs = 8 V, Is = 10 mA
I = mA
4.Medium
R1​ = 15 ΩR3​ = 8 ΩIR3​+−V1​6 VR2​15 ΩAR4​4 ΩBIs​?

Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.

V1 = 6 VR1 = 15 ΩR2 = 15 ΩR3 = 8 ΩR4 = 4 Ω
Is = A
5.Hard
R1​ = 6 ΩR2​ = 10 Ω+−VR2​R4​ = 12 Ω+−V1​10 VR3​3 ΩAIs​2.5 AB−+V2​15 V

Use superposition to find the voltage VR2 across R2 with the polarity shown.

V1 = 10 VIs = 2.5 AV2 = 15 VR1 = 6 ΩR2 = 10 ΩR3 = 3 ΩR4 = 12 Ω
VR2 = V
6.Hard
R1​ = 5 ΩR2​ = 5 ΩR4​ = 8 ΩIR4​+−V1​12 VR3​25 ΩAIs​2.5 AB−+V2​10 V

Use superposition to find the power PR4 absorbed by R4.

V1 = 12 VIs = 2.5 AV2 = 10 VR1 = 5 ΩR2 = 5 ΩR3 = 25 ΩR4 = 8 Ω
PR4 = W

Answer key

  1. 1. IR3 = 1.05 A
  2. 2. VA = 18 V
  3. 3. I = 2.8 mA
  4. 4. Is = 0.75 A
  5. 5. VR2 = 20.14 V
  6. 6. PR4 = 50 W

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