Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 6 Ω+−V1​6 VR2​3 ΩAIs​3 A

Use superposition to find the node voltage VA (measured from ground).

V1 = 6 VIs = 3 AR1 = 6 ΩR2 = 3 Ω
VA = V
2.Easy
linear circuitV1​ = 6 VV2​ = 12 VIRL​

A linear resistive circuit contains two independent voltage sources, V1 = 6 V and V2 = 12 V. With both sources on, the current through the load resistor is I = 24 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 13 mA. Find the load current I when V1 is raised to 12 V and V2 stays at 12 V.

I = 24 mA (both sources)I = 13 mA (only V1)
I = mA
3.Medium
R1​ = 2 ΩIR1​R3​ = 12 Ω+−V1​24 VR2​15 ΩAR4​6 ΩBIs​5 A

Use superposition to find the power PR1 absorbed by R1.

V1 = 24 VIs = 5 AR1 = 2 ΩR2 = 15 ΩR3 = 12 ΩR4 = 6 Ω
PR1 = W
4.Medium
R1​ = 10 ΩR3​ = 5 Ω+−V1​24 VR2​8 ΩAR4​20 Ω−+VR4​BIs​4 A

Use superposition to find the voltage VR4 across R4 with the polarity shown.

V1 = 24 VIs = 4 AR1 = 10 ΩR2 = 8 ΩR3 = 5 ΩR4 = 20 Ω
VR4 = V
5.Hard
R1​ = 12 ΩR2​ = 5 ΩR4​ = 2 Ω+−V1​24 VR3​15 Ω+−VR3​AIs​3 AB+−V2​18 V

Use superposition to find the voltage VR3 across R3 with the polarity shown.

V1 = 24 VIs = 3 AV2 = 18 VR1 = 12 ΩR2 = 5 ΩR3 = 15 ΩR4 = 2 Ω
VR3 = V
6.Hard
R1​ = 20 ΩR2​ = 25 ΩR4​ = 4 Ω+−V1​6 VR3​2 ΩIR3​AIs​3 AB+−V2​18 V

Use superposition to find the power PR3 absorbed by R3.

V1 = 6 VIs = 3 AV2 = 18 VR1 = 20 ΩR2 = 25 ΩR3 = 2 ΩR4 = 4 Ω
PR3 = W

Answer key

  1. 1. VA = 8 V
  2. 2. I = 37 mA
  3. 3. PR1 = 2.072 W
  4. 4. VR4 = 18.42 V
  5. 5. VR3 = 18.54 V
  6. 6. PR3 = 2.606 W

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