Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

A linear resistive circuit contains two independent voltage sources, V₁ = 12 V and V₂ = 6 V. With both sources on, the current through the load resistor is I = 11.5 mA. With V₂ switched off (replaced by a short circuit) and V₁ unchanged, the load current is 16.5 mA. Find the load current I when V₁ is raised to 24 V and V₂ stays at 6 V.

I = 11.5 mA (both sources)I = 16.5 mA (only V₁)

I = mA

2.Easy

Use superposition to find the node voltage V_A (measured from ground).

V₁ = 6 VI_s = 3 AR₁ = 10 ΩR₂ = 10 Ω

V_A = V

3.Medium

Use superposition to find the power P_R4 absorbed by R₄.

V₁ = 30 VI_s = 3 AR₁ = 20 ΩR₂ = 12 ΩR₃ = 4 ΩR₄ = 20 Ω

P_R4 = W

4.Medium

Use superposition to find the current I_R1 through R₁ in the direction of the arrow.

V₁ = 15 VI_s = 2.5 AR₁ = 20 ΩR₂ = 10 ΩR₃ = 20 ΩR₄ = 5 Ω

I_R1 = A

5.Hard

Use superposition to find the power P_R3 absorbed by R₃.

V₁ = 12 VI_s = 2 AV₂ = 5 VR₁ = 6 ΩR₂ = 25 ΩR₃ = 2 ΩR₄ = 10 Ω

P_R3 = W

6.Hard

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 6 VI_s = 0.5 AV₂ = 9 VR₁ = 10 ΩR₂ = 2 ΩR₃ = 4 ΩR₄ = 12 Ω

I_R2 = A

Answer key

1. I = 28 mA
2. V_A = 18 V
3. P_R4 = 42.19 W
4. I_R1 = 0.4211 A
5. P_R3 = 1.71 W
6. I_R2 = −0.7881 A

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