Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
R1​ = 10 ΩR2​ = 2 ΩIR2​+−V1​8 VR3​6 ΩA+−V2​24 V

Use superposition to find the current IR2 through R2 in the direction of the arrow.

V1 = 8 VV2 = 24 VR1 = 10 ΩR2 = 2 ΩR3 = 6 Ω
IR2 = A
2.Easy
R1​ = 5 ΩIR1​R2​ = 2 Ω+−V1​15 VR3​3 ΩA+−V2​6 V

Use superposition to find the contribution IR1′ of V1 alone to the current IR1 through R1 in the direction of the arrow.

V1 = 15 VV2 = 6 VR1 = 5 ΩR2 = 2 ΩR3 = 3 Ω
IR1′ = A
3.Medium
R1​ = 4 ΩR3​ = 3 Ω+−V1​10 VR2​6 ΩAR4​5 Ω+−VR4​BIs​3 A

Use superposition to find the voltage VR4 across R4 with the polarity shown.

V1 = 10 VIs = 3 AR1 = 4 ΩR2 = 6 ΩR3 = 3 ΩR4 = 5 Ω
VR4 = V
4.Medium
R1​ = 10 ΩR3​ = 10 ΩIR3​+−V1​15 VR2​3 ΩAR4​15 ΩBIs​?

Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.

V1 = 15 VR1 = 10 ΩR2 = 3 ΩR3 = 10 ΩR4 = 15 Ω
Is = A
5.Hard
linear circuitV1​V2​Is​IRL​

A linear resistive circuit contains three independent sources: V1, V2 and Is. The current I through a load is measured three times. With all sources at their normal values, I = −0.5 mA. With V1 doubled and the other two unchanged, I = −9.5 mA. With the direction of Is reversed and the other two unchanged, I = −13.5 mA. Find the load current I when V2 is switched off and V1 and Is have their normal values.

normal: I = −0.5 mA2·V1: I = −9.5 mA−Is: I = −13.5 mA
I = mA
6.Hard
R1​ = 25 ΩR2​ = 8 ΩR4​ = 3 Ω+−V1​12 VR3​30 Ω+−VR3​AIs​5 AB+−V2​36 V

Use superposition to find the voltage VR3 across R3 with the polarity shown.

V1 = 12 VIs = 5 AV2 = 36 VR1 = 25 ΩR2 = 8 ΩR3 = 30 ΩR4 = 3 Ω
VR3 = V

Answer key

  1. 1. IR2 = −3.652 A
  2. 2. IR1′ = 2.419 A
  3. 3. VR4 = −4.904 V
  4. 4. Is = 0.2308 A
  5. 5. I = −2.5 mA
  6. 6. VR3 = 31.15 V

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