Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
R1​ = 4 ΩR2​ = 5 Ω+−V1​6 VR3​4 ΩIR3​A+−V2​18 V

Use superposition to find the contribution IR3′ of V1 alone to the current IR3 through R3 in the direction of the arrow.

V1 = 6 VV2 = 18 VR1 = 4 ΩR2 = 5 ΩR3 = 4 Ω
IR3′ = A
2.Easy
R1​ = 6 ΩR2​ = 5 Ω+−V1​20 VR3​6 ΩIR3​A+−V2​20 V

Use superposition to find the current IR3 through R3 in the direction of the arrow.

V1 = 20 VV2 = 20 VR1 = 6 ΩR2 = 5 ΩR3 = 6 Ω
IR3 = A
3.Medium
R1​ = 15 ΩIR1​R3​ = 10 Ω+−V1​30 VR2​10 ΩAR4​6 ΩBIs​2 A

Use superposition to find the current IR1 through R1 in the direction of the arrow.

V1 = 30 VIs = 2 AR1 = 15 ΩR2 = 10 ΩR3 = 10 ΩR4 = 6 Ω
IR1 = A
4.Medium
linear circuitVs​Is​IRL​

A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 15 V and Is = 10 mA, I = 17.5 mA; with Vs = 15 V and Is = 5 mA, I = 16.25 mA. Find the load current I when Vs = 5 V and Is = 8 mA.

15 V, 10 mA → 17.5 mA15 V, 5 mA → 16.25 mAVs = 5 V, Is = 8 mA
I = mA
5.Hard
R1​ = 20 ΩR2​ = 5 ΩR4​ = 20 Ω+−V1​18 VR3​3 ΩIR3​AIs​1.5 AB+−V2​?

Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.

V1 = 18 VIs = 1.5 AR1 = 20 ΩR2 = 5 ΩR3 = 3 ΩR4 = 20 Ω
V2 = V
6.Hard
R1​ = 12 ΩIR1​R2​ = 2 ΩR4​ = 4 Ω+−V1​10 VR3​15 ΩAIs​3 AB−+V2​15 V

Use superposition to find the power PR1 absorbed by R1.

V1 = 10 VIs = 3 AV2 = 15 VR1 = 12 ΩR2 = 2 ΩR3 = 15 ΩR4 = 4 Ω
PR1 = W

Answer key

  1. 1. IR3′ = 0.5357 A
  2. 2. IR3 = 2.292 A
  3. 3. IR1 = −1.636 A
  4. 4. I = 7 mA
  5. 5. V2 = 7.5 V
  6. 6. PR1 = 38.8 W

Full step-by-step solutions: practise this topic on examproblems.com.