A linear resistive circuit contains two independent voltage sources, V1 = 10 V and V2 = 15 V. With both sources on, the current through the load resistor is I = 23 mA. With V2 switched off (replaced by a short circuit) and V1 unchanged, the load current is 15.5 mA. Find the load current I when V1 is switched off and only V2 = 15 V is active.
Superposition worksheet with answers
1.Easy
I = 23 mA (both sources)I = 15.5 mA (only V1)
I = mA
2.Easy
Use superposition to find the current IR2 through R2 in the direction of the arrow.
V1 = 20 VV2 = 10 VR1 = 2 ΩR2 = 8 ΩR3 = 4 Ω
IR2 = A
3.Medium
A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 12 V and Is = 6 mA, I = 3 mA; with Vs = 20 V and Is = 2 mA, I = 9 mA. Find the load current I when Vs = 4 V and Is = 10 mA.
12 V, 6 mA → 3 mA20 V, 2 mA → 9 mAVs = 4 V, Is = 10 mA
I = mA
4.Medium
Find the value of the current source Is (direction as shown) that makes the current IR3 through R3 equal to zero.
V1 = 12 VR1 = 10 ΩR2 = 6 ΩR3 = 4 ΩR4 = 10 Ω
Is = A
5.Hard
Use superposition to find the power PR1 absorbed by R1.
V1 = 10 VIs = 0.5 AV2 = 15 VR1 = 10 ΩR2 = 25 ΩR3 = 12 ΩR4 = 12 Ω
PR1 = W
6.Hard
Find the value of the voltage source V2 (polarity as shown) that makes the current IR3 through R3 equal to zero.
V1 = 6 VIs = 4 AR1 = 15 ΩR2 = 12 ΩR3 = 5 ΩR4 = 2 Ω
V2 = V
Answer key
- 1. I = 7.5 mA
- 2. IR2 = 0.3571 A
- 3. I = −3 mA
- 4. Is = 0.45 A
- 5. PR1 = 4.099 W
- 6. V2 = 2.4 V
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