Use superposition to find the current IR3 through R3 in the direction of the arrow.
Superposition worksheet with answers
1.Easy
V1 = 10 VV2 = 6 VR1 = 10 ΩR2 = 8 ΩR3 = 10 Ω
IR3 = A
2.Easy
Use superposition to find the current IR2 through R2 in the direction of the arrow.
V1 = 20 VIs = 3 AR1 = 12 ΩR2 = 8 Ω
IR2 = A
3.Medium
A linear resistive circuit contains one voltage source Vs and one current source Is. The current I through a load resistor is measured twice: with Vs = 6 V and Is = 3 mA, I = 3.9 mA; with Vs = 12 V and Is = 8 mA, I = 8.8 mA. Find the load current I when Vs = 15 V and Is = 10 mA.
6 V, 3 mA → 3.9 mA12 V, 8 mA → 8.8 mAVs = 15 V, Is = 10 mA
I = mA
4.Medium
Use superposition to find the voltage VR4 across R4 with the polarity shown.
V1 = 6 VIs = 1 AR1 = 8 ΩR2 = 20 ΩR3 = 5 ΩR4 = 15 Ω
VR4 = V
5.Hard
Use superposition to find the power PR3 absorbed by R3.
V1 = 5 VIs = 6 AV2 = 30 VR1 = 15 ΩR2 = 25 ΩR3 = 2 ΩR4 = 8 Ω
PR3 = W
6.Hard
Use superposition to find the power PR1 absorbed by R1.
V1 = 36 VIs = 3 AV2 = 15 VR1 = 25 ΩR2 = 25 ΩR3 = 6 ΩR4 = 20 Ω
PR1 = W
Answer key
- 1. IR3 = 0.5385 A
- 2. IR2 = 2.8 A
- 3. I = 11 mA
- 4. VR4 = 8.75 V
- 5. PR3 = 1.084 W
- 6. PR1 = 20.12 W
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