Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the node voltage V_A (measured from ground).

V₁ = 15 VI_s = 2 AR₁ = 5 ΩR₂ = 4 Ω

V_A = V

2.Easy

Use superposition to find the current I_R2 through R₂ in the direction of the arrow.

V₁ = 20 VI_s = 2 AR₁ = 12 ΩR₂ = 5 Ω

I_R2 = A

3.Medium

Use superposition to find the current I_R1 through R₁ in the direction of the arrow.

V₁ = 15 VI_s = 2 AR₁ = 4 ΩR₂ = 4 ΩR₃ = 5 ΩR₄ = 4 Ω

I_R1 = A

4.Medium

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 12 VI_s = 1.5 AR₁ = 4 ΩR₂ = 20 ΩR₃ = 10 ΩR₄ = 5 Ω

I_R3 = A

5.Hard

Use superposition to find the power P_R3 absorbed by R₃.

V₁ = 15 VI_s = 1.5 AV₂ = 5 VR₁ = 25 ΩR₂ = 2 ΩR₃ = 10 ΩR₄ = 25 Ω

P_R3 = W

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 2.5 mA. With V₁ doubled and the other two unchanged, I = 4.5 mA. With the direction of I_s reversed and the other two unchanged, I = 23.5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 2.5 mA2·V₁: I = 4.5 mA−I_s: I = 23.5 mA

I = mA

Answer key

1. V_A = 11.11 V
2. I_R2 = 2.588 A
3. I_R1 = −1.852 A
4. I_R3 = 0.1364 A
5. P_R3 = 15.08 W
6. I = −8.5 mA

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