Superposition worksheet with answers

Free printable Superposition worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy

Use superposition to find the current I_R3 through R₃ in the direction of the arrow.

V₁ = 24 VV₂ = 10 VR₁ = 5 ΩR₂ = 3 ΩR₃ = 10 Ω

I_R3 = A

2.Easy

Use superposition to find the voltage V_R3 across R₃ with the polarity shown.

V₁ = 12 VV₂ = 12 VR₁ = 10 ΩR₂ = 10 ΩR₃ = 2 Ω

V_R3 = V

3.Medium

Find the value of the current source I_s (direction as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 24 VR₁ = 6 ΩR₂ = 8 ΩR₃ = 5 ΩR₄ = 3 Ω

I_s = A

4.Medium

Use superposition to find the power P_R4 absorbed by R₄.

V₁ = 12 VI_s = 1.5 AR₁ = 5 ΩR₂ = 2 ΩR₃ = 12 ΩR₄ = 8 Ω

P_R4 = W

5.Hard

Find the value of the voltage source V₂ (polarity as shown) that makes the current I_R3 through R₃ equal to zero.

V₁ = 6 VI_s = 6 AR₁ = 6 ΩR₂ = 30 ΩR₃ = 12 ΩR₄ = 10 Ω

V₂ = V

6.Hard

A linear resistive circuit contains three independent sources: V₁, V₂ and I_s. The current I through a load is measured three times. With all sources at their normal values, I = 14 mA. With V₁ doubled and the other two unchanged, I = 19.5 mA. With the direction of I_s reversed and the other two unchanged, I = 5 mA. Find the load current I when V₂ is switched off and V₁ and I_s have their normal values.

normal: I = 14 mA2·V₁: I = 19.5 mA−I_s: I = 5 mA

I = mA

Answer key

1. I_R3 = 1.284 A
2. V_R3 = 3.429 V
3. I_s = 4.571 A
4. P_R4 = 9.68 W
5. V₂ = 20 V
6. I = 10 mA

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